题文
(8分)某手机专营店代理销售A、B两种型号手机.手机的进价、售价如下 表:
(1)第一季度:用36000元购进A、B两种型号的手机,全部售完后获利6300元,求 第一季度购进A、B两种型号手机的数量; (2)第二季度:计划购进A、B两种型号手机共34部,且不超出第一季度的购机总费用,则A型号手机最多能购多少部? |
题型:解答题 难度:中档
答案
(1)解:设该专营店第一季度购进A、B两种型号手机的数量分别为x部和y部. 1分 答:该专营店本次购进A、B两种型号手机的数分别为15部和18部.······························································ 4分 (2)解:设第二季度购进A型号手机a部.···················································· 5分 由题意可知:1200a+1000(34-a)≤36000,····················································· 6分 解得:a≤10··························································································· 7分 不等式的最大整数解为10 答:第二季度最多能购A型号手机10部.······················································ 8分 |
据专家权威分析,试题“(8分)某手机专营店代理销售A、B两种型号手机.手机的进价、售价如..”主要考查你对 不等式的性质,不等式的定义,一元一次不等式的解法,一元一次不等式组的定义 等考点的理解。关于这些考点的“档案”如下:
不等式的性质不等式的定义一元一次不等式的解法一元一次不等式组的定义
考点名称:不等式的性质 考点名称:不等式的定义 考点名称:一元一次不等式的解法 考点名称:一元一次不等式组的定义
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