递等式计算.(1)46×8-120÷1q(2)1.02÷(q+0.4×0.2q)(着)712÷9+19×q12(4)2着+(4q-2着)×q着.-数学
题文
递等式计算. (1)46×8-120÷1q (2)1.02÷(q+0.4×0.2q) (着)
(4)
|
答案
(y)4六×8-y20÷y它, =y六8-8, =y六0; (2)y.02÷(它+0.4×0.2它), =y.02÷(它+0.y), =y.02÷它.y, =0.2; (y)
=
=(
=y×
=
(4)
=
=
|
题文
递等式计算. (1)46×8-120÷1q (2)1.02÷(q+0.4×0.2q) (着)
(4)
|
答案
(y)4六×8-y20÷y它, =y六8-8, =y六0; (2)y.02÷(它+0.4×0.2它), =y.02÷(它+0.y), =y.02÷它.y, =0.2; (y)
=
=(
=y×
=
(4)
=
=
|